100% Real Waec Gce 2015 General Mathematics Obj And Theory Answers.

By 09:55 Fri, 11 Sep 2015 Comments


COMPLETE MATHS OBJ:

1CBADBDDBDA

11DCDBACDCCC

21CACBCDCBCA

31ADBACCDCCD

41DBBBDBCAAD

8a)

By using pythagoras

r^2 = (r - 8)^2 + 32^2

r^2 = r^2 - 16r + 64 + 1024

16r = 64 + 1024

r = 1088/16

r = 68

r=68cm

8bi)

{st/pt/

q2=27^2 +12^2

q=sqrt27^2 + 12^2

q=sqrt729+144

q=sqrt873

q=29.5cm

==================================

7a)

|PQ|^2 = |PB|^2 + |BQ|^2

|PQ|^2 = (5 - x )^2 + X^2

|PQ|^2 = 25 - 10x + x^2 + x^2 [note ^ means Raise

to power]

|PQ|^2 = 2x^2 - 10x + 25

NB: PQ = QR (side of a square)

Area of PQRS = PQ x QR

= PQ x PQ = PQ^2

Area of PQRS = (2x^2 - 10x + 25)m square

GIVEN: 2x^2 - 10 + 25 = 3/5 of 25

= 2x^2 - 10x + 10 = 0

= x^2 - 5 + 5 = 0

Using General Formular mthod

X = -(-5) ± Square Root (-5)^2 - 4(1)(5)/ (2 x 1)

X = 5 ± Square Root 25 - 20/ 2

X = 5 ± Square Root 5 / 2

X = 5 + Square Root 5 / 2 OR 5 - Square Root 5 / 2

X = 3.62 or 1.68

7b )

L + a / n - 1 = d ------------ (I)

2s = n (a + 1) ---------------- (2)

From eq (1)

L + a = d (n - 1) -------------- (3)

Put eq (3 into 2)

2s = nd (n-1)

2s = d (n^2 - n)

S = d ( n^2 - n ) / 2 or

S = dn(n-1)/2

==================================

(4a)

Given: Sinx = 3/5

i.e

Using pythogoras triple 3,4,5

CosX + TanX/SinX

=4/5 + 3/4 ÷ 3/5

= 16+15/20 ÷ 3/5

= 31/20 ÷ 3/5

= 31/20 x 5/3

= 31/12

(4b)

=Draw The Diagram=

Reflex P'Q'T + R'Q'T + P'Q'R = 360 (sum at a point)

200 + 32 + P'Q'R = 360

232 + P'Q'R = 360

P'Q'R = 360 - 232

P'Q'R = 128°

From the Diagram

Q'R'U = P'Q'R = 128° (alternate angles)

X = Q'R'U + S'R'U

X = 128° + 180

X = 308°

==================================

5a)

1. | 2. | 3. | 4. | 5. | 6. |

------------------------------------------

1|1,1|1,2 |1,3 |1,4 |1,5 |1,6 |

-------------------------------------------

2|2,1|2,2 |2,3 |2,4 |2,5|2,6 |

--------------------------------------------

3|3,1|3,2 |3,3 |3,4 |3,5|3,6 |

---------------------------------------------

4|4,1|4,2 |4,3 |4,4 |4,5|4,6 |

---------------------------------------------

5|5,1|5,2 |5,3 |5,4 |5,5|5,6 |

-----------------------------------------------

6|6,1|6,2 |6,3 |6,4 |6,5|6,6 |

------------------------------------------------

B) pr(sum of outcome is 8)

= 4/36 = 1/9

Bii) pr(product of outcom 2[1/2 (x+2)] + 2(x+1) = 17

x + 2 + 2x = 17

3x + 2 = 17

3x = 17 - 2

3x = 15

x = 15/3

x = 5

(3ai) Perimeter of garden

= 4x

= 4 x 5

= 20m

(3aii)

=Draw The Diagram=

Area Covered By Both Garden And path

= (x+1) (x+2)

= (5+1) (5+2)

= 6x7

= 42m^2

==================================

2a)

1/x+1/x+3=1/2

L.C.M=x(x+3)

X+3+x/x(x+3)=1/2

2(2x+3)/x(x+3)=1/2

2(2x+3)=x(x+3)

4x+6=x^2+3x

X^2+3x=4x+6

X^2+3x-4x-6=0

X^2-x-6=0

(X^2-3x)+(2x-6)=0

X(x-3)+2(x-3)=0

(X+2)(x-3)=0

X=-2 or x=3

2b)

Let d bag of rice be X

Let d bag of beans be Y

X+Y=17--->(I)

2250x+2400y=39600--->(2)

From eqtn (I)

X=17-y

Using elimination method to eliminate Y

2250x+2250y=38250--->(3)

2250x+2400y=39600--->(4)

Eqtn 4- eqtn 3

2400x-2250x = 39600-38250

150x=1350

X=1350/150

X=9

D trader bought 9bags of beans

==================================

1a)

1/2log 25/4- 2log10 4/5+log10 320/125

Log(25/4)^1/2-log(4/5)^2+log10 320/125

Log10 sqrt25/4-log16/25+log10 320/125

Log10 5/2-log10 16/25+log10 320/125

Log10 5/2+log10 320/125-log10 16/25

Log10 [5/2*320/125÷16/25]

Log10 [5/2*320/125*25/16]

Log10 10=1

1b)

% income= 20%

Grant per land =GHC€15.00

Total population from

2003-2007

=1.2*1.2*1.2*1.2*3000=6220.8

Total grant=population*grant per head

=6220.8*15

=ghc€93312

Total grant=GHC€93312

==================================

6a)

2 X (37)x = 75x

2 X (3x + 7)10 = (7x + 5)10

2 (3x + 7) = 7x + 5

6x + 14 = 7x + 5

14 - 5 = 7x - 6x

9 = x

:- x = 9

6b)

Let The Number Of boys be X

Number Of girls in class = x + 5

GIVEN: x+5/+2 = 5/4

5(x+2) = 4(x+5)

5x + 10 = 4x + 20

5x - 4x = 20 - 10

x = 10

i)Numbers of girsl in class

= x + 5

= 10 + 5

= 15

ii)Total number of students

= x + x + 5

= 10 + 10 + 5

= 25

iii)Probability of selecting a boy as class prefect

= 10/24

= 2/5


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